바이너리를 ASCII로 또는 그 반대로 변환

바이너리를 ASCII로 또는 그 반대로 변환

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이 코드를 사용하여 문자열을 가져 와서 바이너리로 변환합니다.

bin(reduce(lambda x, y: 256*x+y, (ord(c) for c in 'hello'), 0))

이 출력 :

0b110100001100101011011000110110001101111

이 사이트 (오른쪽 사이트)에 넣으면 내 메시지가 hello돌아옵니다. 어떤 방법을 사용하는지 궁금합니다. 바이너리 문자열을 8로 분리 한 다음 해당 값 bin(ord(character))또는 다른 방식으로 일치시킬 수 있다는 것을 알고 있습니다. 정말 더 간단한 것을 찾고 있습니다.

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[ -~]Python 2 의 범위 에 있는 ASCII 문자의 경우 :

>>> import binascii
>>> bin(int(binascii.hexlify('hello'), 16))
'0b110100001100101011011000110110001101111'

반대로:

>>> n = int('0b110100001100101011011000110110001101111', 2)
>>> binascii.unhexlify('%x' % n)
'hello'

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Python 3.2 이상 :

>>> bin(int.from_bytes('hello'.encode(), 'big'))
'0b110100001100101011011000110110001101111'

반대로:

>>> n = int('0b110100001100101011011000110110001101111', 2)
>>> n.to_bytes((n.bit_length() + 7) // 8, 'big').decode()
'hello'

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Python 3에서 모든 유니 코드 문자를 지원하려면 :

def text_to_bits(text, encoding='utf-8', errors='surrogatepass'):
    bits = bin(int.from_bytes(text.encode(encoding, errors), 'big'))[2:]
    return bits.zfill(8 * ((len(bits) + 7) // 8))

def text_from_bits(bits, encoding='utf-8', errors='surrogatepass'):
    n = int(bits, 2)
    return n.to_bytes((n.bit_length() + 7) // 8, 'big').decode(encoding, errors) or '\0'

다음은 단일 소스 Python 2/3 호환 버전입니다.

import binascii

def text_to_bits(text, encoding='utf-8', errors='surrogatepass'):
    bits = bin(int(binascii.hexlify(text.encode(encoding, errors)), 16))[2:]
    return bits.zfill(8 * ((len(bits) + 7) // 8))

def text_from_bits(bits, encoding='utf-8', errors='surrogatepass'):
    n = int(bits, 2)
    return int2bytes(n).decode(encoding, errors)

def int2bytes(i):
    hex_string = '%x' % i
    n = len(hex_string)
    return binascii.unhexlify(hex_string.zfill(n + (n & 1)))

예

>>> text_to_bits('hello')
'0110100001100101011011000110110001101111'
>>> text_from_bits('110100001100101011011000110110001101111') == u'hello'
True

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내장 전용python

다음은 단순한 문자열에 대한 순수한 파이썬 메서드입니다.

def string2bits(s=''):
    return [bin(ord(x))[2:].zfill(8) for x in s]

def bits2string(b=None):
    return ''.join([chr(int(x, 2)) for x in b])

s = 'Hello, World!'
b = string2bits(s)
s2 = bits2string(b)

print 'String:'
print s

print '\nList of Bits:'
for x in b:
    print x

print '\nString:'
print s2

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String:
Hello, World!

List of Bits:
01001000
01100101
01101100
01101100
01101111
00101100
00100000
01010111
01101111
01110010
01101100
01100100
00100001

String:
Hello, World!

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I'm not sure how you think you can do it other than character-by-character -- it's inherently a character-by-character operation. There is certainly code out there to do this for you, but there is no "simpler" way than doing it character-by-character.

First, you need to strip the 0b prefix, and left-zero-pad the string so it's length is divisible by 8, to make dividing the bitstring up into characters easy:

bitstring = bitstring[2:]
bitstring = -len(bitstring) % 8 * '0' + bitstring

Then you divide the string up into blocks of eight binary digits, convert them to ASCII characters, and join them back into a string:

string_blocks = (bitstring[i:i+8] for i in range(0, len(bitstring), 8))
string = ''.join(chr(int(char, 2)) for char in string_blocks)

If you actually want to treat it as a number, you still have to account for the fact that the leftmost character will be at most seven digits long if you want to go left-to-right instead of right-to-left.

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This is my way to solve your task:

str = "0b110100001100101011011000110110001101111"
str = "0" + str[2:]
message = ""
while str != "":
    i = chr(int(str[:8], 2))
    message = message + i
    str = str[8:]
print message

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if you don'y want to import any files you can use this:

with open("Test1.txt", "r") as File1:
St = (' '.join(format(ord(x), 'b') for x in File1.read()))
StrList = St.split(" ")

to convert a text file to binary.

and you can use this to convert it back to string:

StrOrgList = StrOrgMsg.split(" ")


for StrValue in StrOrgList:
    if(StrValue != ""):
        StrMsg += chr(int(str(StrValue),2))
print(StrMsg)

hope that is helpful, i've used this with some custom encryption to send over TCP.

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Are you looking for the code to do it or understanding the algorithm?

Does this do what you need? Specifically a2b_uu and b2a_uu? There are LOTS of other options in there in case those aren't what you want.

(NOTE: Not a Python guy but this seemed like an obvious answer)

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This is a spruced up version of J.F. Sebastian's. Thanks for the snippets though J.F. Sebastian.

import binascii, sys
def goodbye():
    sys.exit("\n"+"*"*43+"\n\nGood Bye! Come use again!\n\n"+"*"*43+"")
while __name__=='__main__':
    print "[A]scii to Binary, [B]inary to Ascii, or [E]xit:"
    var1=raw_input('>>> ')
    if var1=='a':
        string=raw_input('String to convert:\n>>> ')
        convert=bin(int(binascii.hexlify(string), 16))
        i=2
        truebin=[]
        while i!=len(convert):
            truebin.append(convert[i])
            i=i+1
        convert=''.join(truebin)
        print '\n'+'*'*84+'\n\n'+convert+'\n\n'+'*'*84+'\n'
    if var1=='b':
        binary=raw_input('Binary to convert:\n>>> ')
        n = int(binary, 2)
        done=binascii.unhexlify('%x' % n)
        print '\n'+'*'*84+'\n\n'+done+'\n\n'+'*'*84+'\n'
    if var1=='e':
        aus=raw_input('Are you sure? (y/n)\n>>> ')
        if aus=='y':
            goodbye()

참고URL : https://stackoverflow.com/questions/7396849/convert-binary-to-ascii-and-vice-versa